In a certain lottery, you must select 5 numbers (in any order) out of 33 correctly to win.
a. How many ways can 5 numbers be chosen out of 33 numbers?
b. You purchase one lottery ticket. What is the probability of winning?
Solution:- by using above data
Use that combination with n = 33 and r = 5
a. definition Combination Cn,r = n!/r!(n-r)!
33C5 = 33!/(33!*28!) = 237336
b. The probability of winning one lottery ticket =
0.00000421
P(win) = number of favorable outcomes/number of possible
outcomes
= 1/237336
=
0.00000421
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